Jill BioSkop
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- May 13, 2010
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So I found this puzzle in a book:
You have two adjacent frictionless planes with a frictionless chain resting on them. One is at a smaller angle from the vertical axis than the other, and this one has less links of the chain resting on it (see fig. 1).
Fig. 1 :
(Please forgive crappy mouse drawings.)
Does the chain slide?
#Answer given in the book:
No, because: suppose you link the chain with itself to form a complete circle (see fig. 2), then if the chain slides it will cause perpetual motion to occur. And perpetual motion doesn't exist, hence the chain doesn't slide.
Fig. 2 :
#My beef with the above answer:
Perpetual motion: "motion that continues indefinitely without any external source of energy; impossible in practice because of friction" (wordnetweb.princeton.edu/perl/webwn)
"The most commonly contemplated type of perpetual motion machine is a mechanical system which (supposedly) sustains motion indefinitely, despite losing energy to friction and air resistance. This violates the first law of thermodynamics (conservation of energy)."(http://en.wikipedia.org/wiki/Perpetual_motion)
Other definitions seem to refer to machines that produce more energy than they use. (Eg: overunity devices (referring to devices with an energy efficiency greater than 1.0) (http://en.wikipedia.org/wiki/Perpetual_motion))
From this:
The biggest cause of energy loss in machines is friction. The above hypothesis uses frictionless objects. This removes the biggest obstacle to perpetual motion. If one follows the 'frictionless' criteria to its logical consequences, then the answer given rests on an incoherent argument. Of course, other sources of energy loss could be air/gas around the setup for eg.
Suppose the planes are set up as in fig. 2; then the weight of the chain could pull the whole of it down on one side (down the side which, once you take in account the weight of the links and the support given by the planes, weighs heaviest). However this implies gravity, and gravity can cause loss of energy, but couldn't the part of the chain being pulled down compensates exactly for the part of the chain being pulled up? Couldn't there be, not new energy being made to compensate, but perfect conservation of energy to start with?
I think the answer to the original question depends on the proportion of links on either plane (if there is no friction plane length matters much less, if at all), and hence that there are insufficient data to answer the question.
Agree/disagree? Thoughts?
You have two adjacent frictionless planes with a frictionless chain resting on them. One is at a smaller angle from the vertical axis than the other, and this one has less links of the chain resting on it (see fig. 1).
Fig. 1 :

Does the chain slide?
#Answer given in the book:
No, because: suppose you link the chain with itself to form a complete circle (see fig. 2), then if the chain slides it will cause perpetual motion to occur. And perpetual motion doesn't exist, hence the chain doesn't slide.
Fig. 2 :

#My beef with the above answer:
Perpetual motion: "motion that continues indefinitely without any external source of energy; impossible in practice because of friction" (wordnetweb.princeton.edu/perl/webwn)
"The most commonly contemplated type of perpetual motion machine is a mechanical system which (supposedly) sustains motion indefinitely, despite losing energy to friction and air resistance. This violates the first law of thermodynamics (conservation of energy)."(http://en.wikipedia.org/wiki/Perpetual_motion)
Other definitions seem to refer to machines that produce more energy than they use. (Eg: overunity devices (referring to devices with an energy efficiency greater than 1.0) (http://en.wikipedia.org/wiki/Perpetual_motion))
From this:
The biggest cause of energy loss in machines is friction. The above hypothesis uses frictionless objects. This removes the biggest obstacle to perpetual motion. If one follows the 'frictionless' criteria to its logical consequences, then the answer given rests on an incoherent argument. Of course, other sources of energy loss could be air/gas around the setup for eg.
Suppose the planes are set up as in fig. 2; then the weight of the chain could pull the whole of it down on one side (down the side which, once you take in account the weight of the links and the support given by the planes, weighs heaviest). However this implies gravity, and gravity can cause loss of energy, but couldn't the part of the chain being pulled down compensates exactly for the part of the chain being pulled up? Couldn't there be, not new energy being made to compensate, but perfect conservation of energy to start with?
I think the answer to the original question depends on the proportion of links on either plane (if there is no friction plane length matters much less, if at all), and hence that there are insufficient data to answer the question.
Agree/disagree? Thoughts?