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All math help thread

ApostateAbe

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Yes, I can see it now. Thanks for clearing that up and for everything. So frustrating, I've spent so many hours with this only to hear from you now that he mixed it up. Sigh.

One last thing. If I were to write this in a open office spread sheet could I write it like this;

x/xsqrt(x/x)^2+(x/x)^2+(x/x)^2 or

x/xsqrt((x/x)^2+(x/x)^2+(x/x)^2)

or none of the above?
I haven't used Open Office Spreadsheet. I have used Excel. It would be the same kind of code that I used in the previous posts. It would be more like the bottom line, because we need parentheses around everthing that the sqrt covers, but we also need to include asterixes for multiplication, so it would be more like:

x/x*sqrt((x/x)^2+(x/x)^2+(x/x)^2)

I am going away from the computer for a few hours. Glad to help, and good luck with the rest of it.
 

Latro

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Nitpick: sqrt(x^2)=|x|, not x. In that example they coincide, but much of the time they do not.
 

ApostateAbe

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Nitpick: sqrt(x^2)=|x|, not x. In that example they coincide, but much of the time they do not.
That's right. |x| is the absolute value of x, meaning that x either stays positive or it goes from negative to positive. Squaring anything always makes it positive, even if it starts out negative, and x could be either positive or negative.
 

Vrecknidj

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Squaring any real number results in a positive number. Squaring some numbers (such as imaginary ones) results in a negative number.
 

ApostateAbe

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I recently completed the The Bell Curve by Herrnstein and Murray, and I also read relevant chapters in the 1996 expanded edition of Stephen J. Gould's The Mismeasure of Man, which claims on its cover to be "The definitive refutation of the argument of The Bell Curve." It contains an added chapter directly rebutting The Bell Curve, which is the same as an essay published in the New Yorker ("Curveball") and in at least one other anthology of responses to The Bell Curve.

Gould writes on pages 375-276 the following passage (this passage requires some mathematical knowledge to understand):
My charge of disingenuousness receives its strongest affirmation in a sentence tucked away on the first page of Appendix 4, page 593, where the authors state: "In the text, we do not refer to the usual measure of goodness of fit for multiple regressions, R^2, but they are presented here for the cross-sectional analysis." Now why would they exclude from the text, and relegate to an appendix that very few people will read or even consult, a number that, by their own admission, is "the usual measure of goodness of fit." I can only conclude that they did not choose to admit in the main text the extreme weakness of their vaunted relationships.

Herrnstein and Murray's correlation coefficients are generally low enough by themselves to inspire lack of confidence. (Correlation coefficients measure the strength of linear relationships between variables; positive values run from 0.0 for no relationship to 1.0 for perfect linear relationship.) Although low figures are not atypical in the social sciences for large surveys involving many variables, most of Herrnstein and Murray's correlations are very weak--often in the 0.2 to 0.4 range. Now, 0.4 may sound respectably strong, but--and now we come to the key point--R^2 is the square of the correlation coefficient, and the square of a number between 0 and 1 is less than the number itself, so a 0.4 correlation yields an r-squared of only 0.16. In Appendix 4, then, we discover that the vast majority of measures for R^2 , excluded from the main body of the text, have values less than 0.1. These very low values of R^2 expose the true weakness, in any meaningful vernacular sense, of nearly all the relationships that form the heart of The Bell Curve.​
Even with the required mathematical knowledge, I expect that this passage is still confusing. If perchance it is NOT confusing to you, then please read it again and critically analyze this argument:

"Now, 0.4 may sound respectably strong, but--and now we come to the key point--R^2 is the square of the correlation coefficient, and the square of a number between 0 and 1 is less than the number itself, so a 0.4 correlation yields an r-squared of only 0.16 [...] In Appendix 4, then, we discover that the vast majority of measures for R^2, excluded from the main body of the text, have values less than 0.1. These very low values of R^2 expose the true weakness, in any meaningful vernacular sense, of nearly all the relationships that form the heart of The Bell Curve."

The premises are correct, but the critical problem with Gould's argument, as I see it, is that he writes as though he has his math exactly backward, in an elementary blunder (much like skipping a negative sign). In order to practically interpret values of R^2, you need to take the square root of them (not the square of them), which makes them larger (not smaller). Appendix 4 of The Bell Curve indeed lists low values of r-squared (R^2), but low values of R^2 are not directly reflective of an extremely weak correlation. The main text of The Bell Curve properly communicates the significance of correlations in terms of the “correlation coefficient,” or R. If you have a correlation coefficient (R) between obesity and IQ equal to 0.31, for example, then you can put that in English as “obesity is correlated with IQ by a 31% goodness of fit,” which is a relatively strong correlation given that there are many forces that influence obesity, not just intelligence, as in almost all sociological relationships (a point that Gould grants). If you were to express that value instead as R^2, however, you would have only R^2 = (0.31)^2 = less than 0.1, which Gould would seem to dismiss as much too weak to draw any correlation, as though R^2 (and not R) is the relevant value for drawing such a conclusion.

It would make no sense for Herrnstein and Murray to list the R^2 values instead of the R values as a rhetorical advantage, because the R^2 values are necessarily smaller than R, but they did it seemingly to supply more relevant technical information for those who want to repeat the statistical modeling. They also listed the ChiSquared values, which no lay reader would seriously care about.

Gould was a renowned evolutionary biologist and was eminently authoritative in regression analysis of biological relationships. Therefore, it is far more likely that I made a silly mathematical/rhetorical mistake than did Gould. So, I would love it if anyone can spot my mistake. The only considerable alternative is that Gould consciously misled his readers, which is the most uncomfortable explanation.
 

Melllvar

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This seems to be the R^2 value: https://en.wikipedia.org/wiki/Coefficient_of_determination#Interpretation

In regression, the R2 coefficient of determination is a statistical measure of how well the regression line approximates the real data points. An R2 of 1.0 indicates that the regression line perfectly fits the data.

This also seems relevant: https://en.wikipedia.org/wiki/Pears...t#Interpretation_of_the_size_of_a_correlation

Disclaimer: I actually know very little about statistics, mostly just researched this after reading your post.
 
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I've got a basic differentiation problem I need help with. I have to find the equation of the tangent line of

problemqe.jpg


at x = a. The calculus part is no problem, I can get the derivative and using the slope formula I get:

myans.jpg


but the provided solution is:

bookans.jpg


What I can't figure out is what happened to the 2 in denominator of the middle term in my answer? I'm sure there is something obvious I am overlooking, but I can't figure out what I am doing wrong.
 

Melllvar

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Probably a typo, I solved it and got the exact same thing you did.
 
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Probably a typo, I solved it and got the exact same thing you did.
Really? I've been coming back to this problem for days, trying to figure out how to get that answer. I'm going to be reasonably pissed off if it is just a typo in the solutions.

It is from MIT Open Courseware, by the way. The provided solution is here.
 

Melllvar

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d) f(a)=1/√a and f�(a)= −(1/2)a−3/2, so
y = −(1/2)a3/2(x − a)+1/√a = −a−3/2x + (3/2)a−1/2

^Assuming you mean that, it looks like they have some other typos already. The exponent on the first a on the second line should be negative, and I have no idea what they're doing in general. If you multiply the second line out you get

-(1/2)a^(-3/2)*x + (1/2)a^(5/2) + a^(-1/2)

which doesn't equal the answer either. Unless I'm just making some retarded mistake.

EDIT: Yeah, I think there were two typos on that line, leaving out the negative and leaving out the (1/2)
 
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Yeah, I noticed the exponent too. That part is correct if you make the exponent negative; it's obviously a typo because that term is just the derivative, which is given above. I guess the missing 1/2 is a typo, too. Dammit, now every time I get a problem wrong in this course, I'm going to be suspicious of the answer key. Well, thanks for your help, Melllvar.
 

Words

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Well I'm still in additions, equations and (possibly[or necessarily?] subtractions.)

I don't know why, but I'm thinking about the relationship(s)[or are "operations" not actually "relationships"? But the word "operation" seems to imply a person manipulating values[or variables?] wherein fact the values are not themselves manipulated but is actually the reasoning of the person that is being manipulated(?)] in a certain scenario. Let's say y stuffs are known whereas x stuffs are unknown. Again, I don't know why or how, but I make three scenarios.

1. X + Y1 = Y2
2. Y1 + X = Y2
3. Y1 + Y2 = X

For some reason, scenario 3 for me is the easiest and the most intuitive to solve. It's just piling more stuff on another quantifiable stuff [most likely same kind of object.]

Scenario 2, I'm okay with, because it's just the distance between two objects (I think...).

Scenario 1 is what I can't intuitively get. [or is there actually no difference between scenario 1 and 2? which would be curious, since it always confuses me when its in world-problem-notation[or is "word problem" not a notation?]] Does anyone know any daily observable event scenario 1 could represent?

...needless to say, I have no future in mathematics.
 

HDINTP

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Well i was bored and so i solved some math but there is one i can´t. There is a possibility of mistake in assignment but i think it is more likely problem of my blindness. So:

On opposite sides of the river two trees grow, how wide is the river there if we meassure the range 20 meters from one tree and then we see the second tree on the opposite side of the river under the angle of 1,136 degrees.

I would like to get it explained step by step.
Thank you and sorry for my english.
 

Jah

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Well I'm still in additions, equations and (possibly[or necessarily?] subtractions.)

I don't know why, but I'm thinking about the relationship(s)[or are "operations" not actually "relationships"? But the word "operation" seems to imply a person manipulating values[or variables?] wherein fact the values are not themselves manipulated but is actually the reasoning of the person that is being manipulated(?)] in a certain scenario. Let's say y stuffs are known whereas x stuffs are unknown. Again, I don't know why or how, but I make three scenarios.

1. X + Y1 = Y2
2. Y1 + X = Y2
3. Y1 + Y2 = X

For some reason, scenario 3 for me is the easiest and the most intuitive to solve. It's just piling more stuff on another quantifiable stuff [most likely same kind of object.]

Scenario 2, I'm okay with, because it's just the distance between two objects (I think...).

Scenario 1 is what I can't intuitively get. [or is there actually no difference between scenario 1 and 2? which would be curious, since it always confuses me when its in world-problem-notation[or is "word problem" not a notation?]] Does anyone know any daily observable event scenario 1 could represent?

...needless to say, I have no future in mathematics.


Yeah, 1 and 2 are the same.
 

A22

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I REALLY need help with CHALLANGE you to solve the following limit:

lim(x->-infinite)((x²+(x³+1)^1/3)^1/2 - (x²-2x)^1/2)

Working only with the real numbers.

A: -3/2

WolframAlpha wouldn't load the steps (too many perhaps?) At least it generated an image so it's more readable:

6948546910_a6484d55db.jpg
 

DetachedRetina

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Usually at this stage of a course they insert the r just because it has to be there, since you get the wrong answer otherwise. The most concrete way to see this is to try to get the area of a circle using polar coordinates; if you just integrate 1 with theta from 0 to 2pi and r from 0 to R, you'll get 2piR, which is obviously not the area of a circle. If you put the r in, you get 2pi (R^2/2) = piR^2.

The actual reason this works is because when you make the coordinate transformation from cartesian to polar coordinates, you change the area of a small region of the space by a certain amount. That is, the area of a box of the form [a,a+da] x [b,b+db] in cartesian coordinates and a "box" of the from [r,r+dr] x [t,t+dt] are not the same.

This is easiest to see when the transformation is linear, such as mapping a coordinate system whose basis is [1,0], [0,1] into one whose basis is, say, [1,2], [3,1]. A 1x1 box in the first coordinate system is just a 1x1 square, which has area 1. A "1x1 box" in the second coordinate system is a parallelogram in the standard coordinate system. This can be seen by drawing the vertices [0,0], [1,2], [3,1], and [1+3,2+1]=[4,3] and connecting them to form a parallelogram. It is clear without even having to do any arithmetic that the area of this region is different from the area of the first region, despite the fact that the second region can be described as a 1x1 box in a coordinate system.

It is a theorem of linear algebra (no calculus required), that when you make a coordinate transformation from the standard basis [1,0,0...,0], [0,1,0,...], ..., [0,0,...,1] to a new basis v1,v2,...,vn, the "volume" of the 1x1x1x...x1 "box" in the new coordinate system is the determinant of the matrix whose rows (or columns) are v1,v2,...,vn. You may recall that the determinant that you get when you put two vectors in 2 dimensions into a matrix is the area of a paralleogram, while the same thing in 3 dimensions results in the volume of a parallelopiped. This generalizes that result, essentially.

When your region is not defined by a linear transformation but is instead defined by a curvy sort of transformation, like the one from Cartesian to polar coordinates, the idea is actually fairly similar: get the best linear approximation of the transformation at each point, and then multiply by the determinant of that matrix at each point, and add up the result with an integral in the usual way. This matrix corresponding to the best linear approximation is the Jacobian, and for the polar coordinate transformation matrix its determinant at (r,t) is r.

Intuitively, the area of the "box" [r,r+dr] x [t,t+dt] is r dr dt. Or, since theta is constant here, the area of an infinitely thin annulus extending from r to r+dr is 2pi r dr. This should begin to click now if it hasn't already: as you add up the circumferences of circles over varying radii beginning at 0, you fill out the area of a circle.



Incidentally, I really really wish someone would create a hybrid, perhaps year-long linear algebra+Calculus 3 course. So many things like this could be clearer this way.

What a great description of what the Jacobian is. I really liked linear algebra when I took it, and I wish it was required math to take before all the calculus. Anyways I think your answer would have been acknowledged earlier if you put that intuitive explanation first. Have you considered teaching math? My professor struggled to even describe what a determinate was and why it was important. He had us derive matrix division by multiplying a known matrix by a mystery matrix such that the product equals ONE. This weird term kept cropping up which was of course the determinate. What a silly way to convey the idea. Maybe that would be a good homework problem after first grasping why the "scaling factor" is there in the first place.
Anyways I'm probably not being clear.
 

Agent Intellect

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I REALLY need help with CHALLANGE you to solve the following limit:

lim(x->-infinite)((x²+(x³+1)^1/3)^1/2 - (x²-2x)^1/2)

Working only with the real numbers.

A: -3/2

WolframAlpha wouldn't load the steps (too many perhaps?) At least it generated an image so it's more readable:

6948546910_a6484d55db.jpg

Try multiplying by the conjugate over the conjugate and then by (1/X)/(1/X). If you don't know what I'm talking about, check out this video (specifically the second problem).
 

DetachedRetina

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A wolfram alpha type google docs would be a great idea. Get on it google.
 

Sanctum

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No statistics?
 

A22

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I forgot to thank you, Agent Intellect. Thank you.

...

I need help integrating this: ((1+(1/x))^(-3))*(1/x²)

I got to -u^-2 / 2 (which is -1/2u²), but when you should replace u with it's original value, Wolfram lost me. I've done this over and over and I always get -1/2(1+1/x)²

I compared my answer to Wolfram's and it didn't return "True" so... halp

semttuloqc.gif
 

ApostateAbe

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I forgot to thank you, Agent Intellect. Thank you.

...

I need help integrating this: ((1+(1/x))^(-3))*(1/x²)

I got to -u^-2 / 2 (which is -1/2u²), but when you should replace u with it's original value, Wolfram lost me. I've done this over and over and I always get -1/2(1+1/x)²

I compared my answer to Wolfram's and it didn't return "True" so... halp
Maybe I can halp.

1/(2*u^2)
=1/(2*(x^-1+1)^2)
=1/(2*(x^-2+2*x^-1+1))

Multiply top and bottom by x^2.

1/(2*(x^-2+2*x^-1+1))
=x^2/(2*(1+2*x+x^2))
=x^2/(2*(x^2+2*x+1))
=x^2/(2*(x+1)^2)

I don't know how to continue with the bit about "Which is equivalent for restricted x values to..." but maybe that's all you need.
 

SLushhYYY

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I forgot to thank you, Agent Intellect. Thank you.

...

I need help integrating this: ((1+(1/x))^(-3))*(1/x²)

I got to -u^-2 / 2 (which is -1/2u²), but when you should replace u with it's original value, Wolfram lost me. I've done this over and over and I always get -1/2(1+1/x)²

I compared my answer to Wolfram's and it didn't return "True" so... halp

Not too hard my friend.

1/(((1+(1/x))^3)*(x^2))dx where u=1/x ; du=-1/x^2

So ---> -1/((1+u))^3)du

Integral of -1/((1+u))^3)du is 1/2(u+1)^2

Now plug the original (u) value into 1/2(u+1)^2

So the answer is 1/2((1/x)+1)^2 + C
 

A22

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Thank you both. It turns out it was just another way of writing the same thing, which I realized with Abe's post. Calculus is fun, but I get pissed when I can't solve those damn integrals and derivatives. e^x, ln x and x^x were a pain in the ass 'til I got the hang of it. Thing is, I don't learn much in college, I learn most stuff from books they tell me to read / the internet.
 

ApostateAbe

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Thank you both. It turns out it was just another way of writing the same thing, which I realized with Abe's post. Calculus is fun, but I get pissed when I can't solve those damn integrals and derivatives. e^x, ln x and x^x were a pain in the ass 'til I got the hang of it. Thing is, I don't learn much in college, I learn most stuff from books they tell me to read / the internet.
You are welcome, feel free to ask again.
 
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