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- Feb 5, 2019
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@Utisz that was my interpretation yes.
The answer I got is a bit different (don't want to post too much because it might give away the answer to the open question). We could maybe return to this once the question closes?
But as long as they are not all of unique cardinality (which they can't be, since the minimum average for that case would be (n+1)/2 = 1 trillion + 0.5 ), then clearly at least 2 must have the same cardinality
unless you're looking for the maximum multiplicity of cardinalities, which would be a slightly more challenging problem![]()
I posted an example I hope helps to clarify. I guess we could say it is the minimum (over all assignments of stars to galaxies) of the maximum multiplicity of cardinalities (if I understand the last part correctly).

So for every assignment of stars to galaxies, we consider what is the size of the largest group of galaxies with the same number of stars? And then we take the minimum of that value over all possible assignments. Does that make sense?