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6÷2(1+2)

Minute Squirrel

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I know this is old, but I just had to sit down for 20 mins and teach abunch of mf elementary school math for them to get the right answer.

It's 9 btw

If you think it's any number other than 9 you need to kick yourself or your math teacher in the balls/cunny because you're wrong.

If you're even one of those fuckers that thinks it's "ambiguous" still kick yourselves in the balls.

Jesus Christ that was the most frustrating 25mins I've had in a long ass time.
 

Grayman

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dont forget that 0/0 is 1 which can be proven
 

Minute Squirrel

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dont forget that 0/0 is 1 which can be proven

I'm pretty sure it's undefined/indeterminate. So I guess you're kind of right in that it could equal 1 but you're mostly wrong. But tbh I feel like I'm missing some kind of joke...
 

Grayman

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I'm pretty sure it's undefined/indeterminate. So I guess you're kind of right in that it could equal 1 but you're mostly wrong. But tbh I feel like I'm missing some kind of joke...


2/0 is undefined because no number times zero can possibly give you two. All numbers will result in zero and so there isn't an answer.

0/0 is not undefined because because 0 * 0 = 0 also it is the whole of itself so it is also 1 as 0 = 0 * 1 proves this as well. It satisfies bot rules but does not satisfy the rule required to be undefined which is that no answer can be given.

Finally,

Simplification cannot function if 0/0 is not 1.

1 = x/x = (x-1)/(x-1) = (x-2)/(x-2) = (x-3)/(x-3) = ... to (x-infinity)/(x-infinity) = (x+1)/(x+1) = (x+2)/(x+2) = (X+3)/(x+3) = ... to (x+infinity)/(x+infinity)

If x is any number the result will be undefined in the above unless 0/0 is 1 then the answer will be true that all these are equal to 1 and simplification is still a valid tool in math.




************
As to your equation...

Its confusing when in its abbreviated form because the 2 looks like it is part of the brackets/parenthesis unless written in full form 6÷2*(2+1) first.


But...?
6÷2y = 3/y or 6÷2*y = 3y assuming y = (2+1)
 

Minute Squirrel

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2/0 is undefined because no number times zero can possibly give you two. All numbers will result in zero and so there isn't an answer.

0/0 is not undefined because because 0 * 0 = 0 also it is the whole of itself so it is also 1 as 0 = 0 * 1 proves this as well. It satisfies bot rules but does not satisfy the rule required to be undefined which is that no answer can be given.

Finally,

Simplification cannot function if 0/0 is not 1.

1 = x/x = (x-1)/(x-1) = (x-2)/(x-2) = (x-3)/(x-3) = ... to (x-infinity)/(x-infinity) = (x+1)/(x+1) = (x+2)/(x+2) = (X+3)/(x+3) = ... to (x+infinity)/(x+infinity)

If x is any number the result will be undefined in the above unless 0/0 is 1 then the answer will be true that all these are equal to 1 and simplification is still a valid tool in math.

Yes, you're right. Undefined wasn't the proper term to be used. Indeterminate is what I meant but I ended up lumping the two terms together. The reason I put undefined/indeterminate was because I wasn't sure which one was correct or if they were interchangeable. 0/0 can be one, but it could also be any other number. I.e. 0=0*48.561439825739391



************
As to your equation...

Its confusing when in its abbreviated form because the 2 looks like it is part of the brackets/parenthesis unless written in full form 6÷2*(2+1) first.


But...?
6÷2y = 3/y or 6÷2*y = 3y assuming y = (2+1)



6/2(3) is 9 because you work from left to right.

There's this whole argument about implicit vs explicit multiplication that goes with this but I think it's fairly simple. 6/2y is still 3y. Why? Well because if you wanted it to be 3/y then you should've written it as 3/(2y). You may ask 'why not write it as (6/2)y?' Well the answer is simple. We evaluate from left to right and parentheses are used when we want to show that certain parts of the expression take precedence. So following this rule it makes sense that 6/(2y) should be how it's written out IF you desire for 2y to take precedence over 6/2.
 

Minute Squirrel

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Ok, after reading more about this I conced that this is ambiguous and thus retract my statement that people who also believe the question is ambiguous should kick themselves in the nuts.

That being said any self respecting mathematician would still say that despite the expression being written (by some smug douchebag) in an ambiguous way by convention the answer is still 9 and that the WHOLE POINT of convention is to make so that even when problems are ambiguous an answer can still be found on a consistent basis.

EDIT: Well apparently Richard Feynman would disagree with me...so on that note I'm just going to show myself out, admit I'm an idiot, and kick myself in balls.
 

Ex-User (14663)

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I don't see any ambiguities about it. Multiplication and division have the same precedence so you read it left-to-right.
 

gps

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I seem to recall a lengthy thread on this on LinkedIn a few years back ... for those with LinkedIn accounts.

Somebody or other made the assertion,
The perpetuation of this outmoded means of expressing precedence -- whether via `B' for brackets or `P' for parentheses, `O' or `E', and MDAS -- is ridiculous and I'm here to ridicule it.
It's a hold-over from a bygone era ... and it's a shame that it was injected into a one-size-fits-all curriculum imposed upon subjects of compulsory miseducation.

So for those without easy access to that LinkedIn Thread, I suppose this quote can serve as a point of departure advocating the replacement of PEMDAS with demonstrably BETTER notations for expressing the same semantics.
 

gps

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For those curious enough, some programming languages permitting the functional programming paradigm allow the semantics of 6÷2(1+2) to be expressed less obtusely and without the totally extraneous EMDAS stages by ONLY using nested parentheses:

Code:
(* (/ 6 2) (+ 1 2))
This symbolic expression is so basic and fundamental to members of the lisp family in both the common lisp and uncommon lisp (EG scheme) branches that it can be evaluated via the REPLs of Gimp (EG scriptfu), Grace/Common_music, Guiled (as the official scripting language of GNU/Gnome), common lisp, autolisp/visual_lisp (as found in AutoCad, IntelliCAD, BrixCAD, etc), and tryScheme

Why impose the rote memorization of PEMDAS when authorial intent could allow school kids to nest parentheses to unambiguously express their intentions and read each other's symbolic expressions?
To pander to the math priesthood ... to help that math teacher to justify his or her pay check?And, while we're at it, infix -- or `inflix' as Seymour Papert called over on Yahoo's Logo Forum about a decade or more ago -- sucks out loud as it can promote the superstitious belief that all operands somehow MUST be operated-upon in a pairwise fashion ... which is patently as untrue for the addition of (1 + 2) as it would be for (1 + 2 + 3) which the fully-parenthesized prefix notation of the lisps would represent as (+ 1 2 3)

PEMDAS is demonstrably DESTRUCTIVE in that those inculcated have UNLEARN it to either get a better grasp of the metaphysics underpinning the notation OR exploit said metaphysics -- commutitivity and associativity, namely -- when crafting symbolic expressions in *some* programming languages.
Why make the precious little darlings learn it to begin with?

There aren't enough good reasons to keep it, are reasons to NOT inculcate it -- as I've presented -- so I say bin it!
 

Jennywocky

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I don't see any ambiguities about it. Multiplication and division have the same precedence so you read it left-to-right.

I agree, although I guess people get confused because as gps notes (I think) it's a notation issue and parens serve multiple purposes (to group OR to multiply) in communication so maybe the notation could be cleaner nowadays.

If parens were used to just group, for example, and the multiplication was explicit using the x or * symbols, then it would be cleaner, as far as having the notation revised.
 

Ex-User (14663)

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2/0 is undefined because no number times zero can possibly give you two. All numbers will result in zero and so there isn't an answer.

0/0 is not undefined because because 0 * 0 = 0 also it is the whole of itself so it is also 1 as 0 = 0 * 1 proves this as well. It satisfies bot rules but does not satisfy the rule required to be undefined which is that no answer can be given.

Finally,

Simplification cannot function if 0/0 is not 1.

1 = x/x = (x-1)/(x-1) = (x-2)/(x-2) = (x-3)/(x-3) = ... to (x-infinity)/(x-infinity) = (x+1)/(x+1) = (x+2)/(x+2) = (X+3)/(x+3) = ... to (x+infinity)/(x+infinity)

If x is any number the result will be undefined in the above unless 0/0 is 1 then the answer will be true that all these are equal to 1 and simplification is still a valid tool in math.




************
As to your equation...

Its confusing when in its abbreviated form because the 2 looks like it is part of the brackets/parenthesis unless written in full form 6÷2*(2+1) first.


But...?
6÷2y = 3/y or 6÷2*y = 3y assuming y = (2+1)

Ptetty sure that 0/0 thing isn't gonna work out. If you have x/y and you let x go to zero from above, then 0/0 will be either 1 or -1 depending on which side y goes to 0 from. So the limit is undefined and you have fucked up all of mathematics.
 

gps

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I agree, although I guess people get confused because as gps notes (I think) it's a notation issue and parens serve multiple purposes (to group OR ...

It IS a notation issue, related to syntactic sugar/vinegar.
If the same semantics can be expressed via two or more notations some will find one notation sweeter than others ... and find those others more of the opposite.
Thus the NEED to NOT WEEN future orthodox twits on PEMDAS, as this outmoded crap CAN become the personal gold standard to which all other notations seem WRONG by comparison ... regardless of superior performance, machine readability, less error-pronedness, more-confidence in it's users, etc, ad nauseum.

... to multiply

What the little buggers just HAVE TO LEARN -- or else -- is the side-by-side juxtaposition of two terms IMPLIES multiplication ... not addition, not subtraction, not division.
And if they don't edit the expression by hand-writing that `*' sign they can end up confused when trying to apply the mnemonic as they might be clever enough to know that M of PEMDAS maps onto `*' ... which was NOT explicitly represented via it's own symbol.

If parens were used to just group, for example, and the multiplication was explicit using the x or * symbols, then it would be cleaner, as far as having the notation revised.

A common source of confusion arises from a one-precedence-level-per-letter-of-mnemonic basis.
The 4 precedence levels would be better expressed P-E-MD-AS ... although as John McCarthy brought to our attention via Lisp notation, the E-MD-AS are operationally extraneous when parentheses can be nested as they already CAN be via P-E-MD-AS.
So rather than exploiting nested parentheses to get the WHOLE job done, a multi-pass algorithm is imposed upon those (mis)using this outmoded system AS WELL AS evaluating innermost parentheticals and plugging the results into whatever next-outermost expressions await their resolution.

McCarthy wasn't the only one to improve upon PEMDAS notation; Ken Iverson delt with the combinatorial explosion otherwise resulting from adding more and more functions willy nilly.
Iverson exploited a stack toppled over to the right; a ticker tape of symbols are evaluated right to left until everything is resolved.
 

Grayman

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Ptetty sure that 0/0 thing isn't gonna work out. If you have x/y and you let x go to zero from above, then 0/0 will be either 1 or -1 depending on which side y goes to 0 from. So the limit is undefined and you have fucked up all of mathematics.


all results are positive since -1/-1 is still 1 unless I am not understanding what you are saying. where is the y from?

A thing divided by itself is always itself.

1 = 44/44 = 0/0 = -2/-2

1 + X = X/X + X unless X is 0?
This can be rewritten as
1 + X = (X+1)/(X+1) +X but now -1 cannot work

simplified
0/0 must equal 1 because

If 0/0 results in 49.47636
then
1=49.47636 + 0 which is false
0/0 is1 then
1=1 + 0 which is true
 

Ex-User (14663)

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If y approaches zero from the negative line then the result is -1. Otherwise it's 1. An analogy to that would be: 0 = -0, so then 0/0 = -0/0, which means 1 = -1
 

QuickTwist

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I was wondering why you had the title as 9 in a cryptic way when I saw this thread tbh.
 

Minute Squirrel

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simplified
0/0 must equal 1 because

If 0/0 results in 49.47636
then
1=49.47636 + 0 which is false
0/0 is1 then
1=1 + 0 which is true

Ok but 49.47636 * 0 = 0
consequently
0/0 = 49.47636

0 can also equal 1 which you have proved. But in other circumstances it could equal any other number. Which is exactly why 0/0 is indeterminate.

A thing divided by itself is always itself.

Zero is not a thing. It is the absence of a thing.


P.S. I didn't change my mind on the expression being ambiguous because of PEDMAS but because of inline division and that(to some serious mathematicians apparently) the obelus can be simply replaced with the slash without any need for parenthesis so that a÷b(c)=a/b(c) where everything right of the slash is in the denominator unless made clear by use of parentheses. At least that's how some people with much higher credentials and knowledge than me see it. I still disagree but that's why it's ambiguous. The answer depends on which convention you use. In reality though I'm CERTAIN(really this time) no self respecting mathematician would write an expression like this unless their intention was to be an ass(or they're just an ass by nature), so yeah.....who ever wrote this expression like this is either stupid or kind of an ass.
 

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Another one: 0 + 0 = 0, so then (0 + 0)/0 = 0/0 + 0/0, which implies 1 = 2
 

gps

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Another one: 0 + 0 = 0, so then (0 + 0)/0 = 0/0 + 0/0, which implies 1 = 2

Why bother with mere addition when we can apply exponentiation and cover the range from 0 right on thru to infinity?

Though if we wander away from the absurdity angle we might extoll -- if not exploit -- the virtues underpinning the calculus.
What if we replace `0' with the venerable `infinitesimal' ... and perhaps represent the/an infinitesimal as 1/infinity?

How small would our notion of either a delta x or infinitesimal BE before using it as both numerator and denominator would no longer equal 1?

Zero is clearly an asymptote in this thought experiment, isn't it?
 

gps

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Zero is not a thing.
It is the absence of a thing.

Is qua IS ... at some level of usage.

I'm pretty sure a few Hindu mathematicians -- the ones that figured out that you needed a symbol to serve as a place holder representing a digit position on an abacus to get polynomial encoding used to represent any/every number in any/every radix.

Zero is NOT the absense of a thing; it is a very precise `thing' firmly bounded between 0-infinitesmal and 0+infinitesimal!
It occupies a specific spot on the Real continuum extending from negative infinity to positive infinity.
Moreover IT serves as a Datum -- a reference -- which gives all OTHER numbers their value ... their semantic MEANING.

Without 0 as a fulcrum, no number -- positive or negative -- could leverage it's identity or utility as a number!
Zero is not a Thing?! It's the King of No-thing.:rolleyes:
 

Ex-User (14663)

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Why bother with mere addition when we can apply exponentiation and cover the range from 0 right on thru to infinity?

Though if we wander away from the absurdity angle we might extoll -- if not exploit -- the virtues underpinning the calculus.
What if we replace `0' with the venerable `infinitesimal' ... and perhaps represent the/an infinitesimal as 1/infinity?

How small would our notion of either a delta x or infinitesimal BE before using it as both numerator and denominator would no longer equal 1?

Zero is clearly an asymptote in this thought experiment, isn't it?

Well, if you replace it with an infinitesimal then there is no problem because you can use calculus to find what this 0/0 actually represents.

For example letting x go to zero from positive real line for x/x^2, then both numerator and denominator go to zero but the limit of the fraction is 0. Doing the same for x/x you get that the limit is 1. And so on.
 

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I know this is old, but I just had to sit down for 20 mins and teach abunch of mf elementary school math for them to get the right answer.

It's 9 btw

If you think it's any number other than 9 you need to kick yourself or your math teacher in the balls/cunny because you're wrong.

If you're even one of those fuckers that thinks it's "ambiguous" still kick yourselves in the balls.

Jesus Christ that was the most frustrating 25mins I've had in a long ass time.

if you had used excel you wouldn't have such problems
 

gps

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if you had used excel you wouldn't have such problems

I like to do my manipulating via non-proprietary software.
SIAG
ses
OpenOffice
Scilab
octave
GNUplot


And you ARE right, BTW.
Doing symbol manipulation manually in the age of machine readable math notations makes about as much sense as making a cake from scratch instead of using a cake mix or buying one ready made.

There are better ways of teaching school children how to commute and associate as per authorial intent ... via `vernacular' notations rather than the antiquated horseshit on par with Liturgical Latin still preached by the tax-funded functionaries of the Math Priesthood.
 

elliptoid

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Well I can tell you that every time this has ever come up I argue fiercely that the answer is 1 and only 1.

Most of the time I find it's people younger than me who believe it is 9, and rarely do those older than me think it is 9. So, something has changed in the education system.

As simple as possible, it is the implied belief that n(A+B) = nA + nB
in other words
The coefficient is simultaneously inside and outside of the parentheses. Neglecting the simultaneity is what produces the answer of 9.
 

elliptoid

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Doing symbol manipulation manually in the age of machine readable math notations makes about as much sense as making a cake from scratch instead of using a cake mix or buying one ready made.

In other words, essential for comprehension.
 

elliptoid

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Makes NO SENSE that a polynomial should change its value depending on whether it's in factored form or not.

So the answer of 9 implies a complete dismissal of basic polynomial rules.
 

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Well I can tell you that every time this has ever come up I argue fiercely that the answer is 1 and only 1.

Most of the time I find it's people younger than me who believe it is 9, and rarely do those older than me think it is 9. So, something has changed in the education system.

As simple as possible, it is the implied belief that n(A+B) = nA + nB
in other words
The coefficient is simultaneously inside and outside of the parentheses. Neglecting the simultaneity is what produces the answer of 9.

That interpretation makes sense only if you distinguish between a*(x + y) and a(x + y). Either that or you read expressions right-to-left.

Neither makes sense in my opinion.

But in the real world, mathematicians would never write that expression in this way anyway. This thing would always be written as a fraction and not a division. The division-style expression will usually come in to play in computer code, where, as far as I know, expressions are always read left-to-right and division and multiplication have the same precedence.
 

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That interpretation makes sense only if you distinguish between a*(x + y) and a(x + y). Either that or you read expressions right-to-left.

Neither makes sense in my opinion.

But in the real world, mathematicians would never write that expression in this way anyway. This thing would always be written as a fraction and not a division. The division-style expression will usually come in to play in computer code, where, as far as I know, expressions are always read left-to-right and division and multiplication have the same precedence.

Indeed.
I don't believe we've yet reached a point in society where computers and their programmers have the authority to dictate their form of logic to the masses.

Math at its simplest can be expressed in word problems, with simple concepts, to solve problems. I challenge anyone to express the equation using words in such a way that one intuitively knows the answer to be 9. Of course I have examples to the contrary, where it makes sense the answer is 1.

In my experience, it is best for the end user to be more intelligent than the computer and add the parentheses as required to circumvent the programming hangups.
 

elliptoid

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No distinction is made between n*(A+B) and n(A+B) not sure what you mean Serac. The argument was in fact to the contrary: they are simultaneous and equally valid, as well as nA+nB

Having completed advanced calculus myself, I can't personally recall any equation from my lifetime wherein it was implied a coefficient was in the denominator without explicit and incontestable notation.
 

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No distinction is made between n*(A+B) and n(A+B) not sure what you mean Serac. The argument was in fact to the contrary: they are simultaneous and equally valid, as well as nA+nB

Having completed advanced calculus myself, I can't personally recall any equation from my lifetime wherein it was implied a coefficient was in the denominator without explicit and incontestable notation.

I guess I have no clue what you mean either. If you suggest a*(x+y) is always treated as a(x+y) then a / b * (x+y) = (a / b) * x + (a / b) * y.

And likewise
a / b (x+y) = (a / b) x + (a / b) y.

This would imply that 6 / 2(1+2) is 9, not 1.

Whereas you claim that a / b(x+y) = a / (b*(x +y))

Also, it is a stupid idea to express math in words. The whole point of math is to avoid that.
 

elliptoid

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I guess I have no clue what you mean either. If you suggest a*(x+y) is always treated as a(x+y) then a / b * (x+y) = (a / b) * x + (a / b) * y.

And likewise
a / b (x+y) = (a / b) x + (a / b) y.

This would imply that 6 / 2(1+2) is 9, not 1.

Whereas you claim that a / b(x+y) = a / (b*(x +y))

I can see you prefer to go in circles and repeat yourself. No matter to me. I don't need to do the same really.

Also, it is a stupid idea to express math in words. The whole point of math is to avoid that.

Absolutely not sir. That is a stupid thing to say.
Have you ever taught math to a child?

The whole point of math is to communicate these abstractions using a universal language. It's not to avoid comprehension, but rather, to enhance. Meh, arrogant fool.

My open challenge is valid regardless of whether you think it is stupid. I think you find it impossible to create a word problem that accurately depicts the equation in such a way the answer is 9, and therefore, are hot and bothered about something which you cannot do, thus, it is a stupid thing. Did I say :arrogant fool: yet?

A failure to execute such a simple task is a failure in methodology in my eyes. :rip:
 

Black Rose

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elliptoid
A ÷ n(x + y)
A ÷ (nx + ny)

Serac
A ÷ n(x + y)
(A ÷ n)*(x + y)

(Don't mind me, I am still playing word games in my IQ thread)
 

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elliptoid
A ÷ n(x + y)
A ÷ (nx + ny)

Right, so what elliptoid suggests is that when you have

a / b * c

Then the order of operation depends on how c came into existence. If it's a sum then you do multiplication first. Otherwise it's the division first.

Once again – a dumb idea.
 

elliptoid

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To be clear, the ferocity of my belief lies in the principal idea that the coefficient is simultaneously inside and outside of the parentheses.

That an equation in factored form conveys no more or less information than it does in expanded form.

There are simple algebraic proofs for this equation.

For example:

let y =2

6÷y(1+y) = 6 ÷ (y+y^2)
=1 (ans)

Another example:

let y = (2+1)
then equation is 6/2y
=1 (ans)

Another example:

A=6
B=2(2+1)

so A/B =z
A = zB
6 = z[2(1+2)]
z=1 (ans)

Source: I copied these from a guy who believes the same thing as me.

And now look here.
Be warned: it's difficult to read and hard on the eyes. Ctrl A Ctrl C Ctrl V to notepad.
 

elliptoid

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Please read the link in earnest as it might change your mind.
 

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To be clear, the ferocity of my belief lies in the principal idea that the coefficient is simultaneously inside and outside of the parentheses.

That an equation in factored form conveys no more or less information than it does in expanded form.

There are simple algebraic proofs for this equation.

For example:

let y =2

6÷y(1+y) = 6 ÷ (y+y^2)
=1 (ans)

Another example:

let y = (2+1)
then equation is 6/2y
=1 (ans)

Another example:

A=6
B=2(2+1)

so A/B =z
A = zB
6 = z[2(1+2)]
z=1 (ans)

Source: I copied these from a guy who believes the same thing as me.

And now look here.
Be warned: it's difficult to read and hard on the eyes. Ctrl A Ctrl C Ctrl V to notepad.

Right, so if you define c = (x+y) then since you consider factors as inside the parenthesis whenever there is a sum inside it, then

a / b * c = a / (b * c)

But if we happen to change c to, say c = x * y, now what? If you want to be consistent, now you have define multiplication as having higher precedence than division. Then expressions like

a / b * y / x

get very different meanings than what one expects as per current notation.

The problem with these things you call "proofs" is that they are not proofs but just examples, special cases, which means you don't consider how this stuff impacts the rest of the mathematics and you run into counter-examples like the ones above.
 

Black Rose

An unbreakable bond
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Multiplication in parentheses now instead of addition.

6÷2(1*2)
6÷2(2)
6÷4
1.5
 

elliptoid

the void is a lie
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lol @ my examples are "special cases"

lol @ word problems are dumb and a bad representative of the essence of math

Buddy you're really talking out of your ass. How am I neglecting the rest of mathematics?
 

gps

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Right, so what elliptoid suggests is that when you have

a / b * c

Then the order of operation depends on how c came into existence.
If it's a sum then you do multiplication first.
Otherwise it's the division first.

Once again – a dumb idea.

Dumb idea irrespective of context, supervening order, or practical considerations?
I'd venture that most -- perhaps unwittingly -- participating in one-or-more Math Orthodoxies share your view ... and perhaps generalize that ANY deviation of `standard practice' enshrined in sacred tradition constitutes a `dumb idea'.

The issue to which @elliptoid alludes -- In the CS domain, anyway-- is `binding'.
When one wants or needs to suspend early-closure, early-certainty -- to which MBTI J types are prone -- typical of the fucktard languages created by Nickle's Worth or his early-binding MBTI-J soul mates which entail values assigned to symbols/variables at COMPILE time pursuant to having a value arise at RUN TIME on a just-in-time basis

If one's desire is to compute as much of an overall expression as possible at compile time while leaving a degree of dynamism open for run time one IS concerned with pre-computing as many sub-expressions as possible to await plug-in values available later ... after compile time has closed with all the trepidation of CLOSURE which J types usually CRAVE ... until they've painted themselves in a corner.

As the Math Priesthood has Sucked Out Loud at integrating what their betters in the domains of Praxis have discovered and implemented as Proof of Concept I'll provide an example which dates back to circa 1962 at the dawn of CAD.
In Propagation of Constraints the relationship between factors acted-upon by would-be `mathematical' operators is established, then when the latest value becomes available it is used to (re)generate the results of the parametric equation.

Order of operations allowing late-binding IS a dumb idea when one is dealing with hide-bound _NTJs who allow Tradition and Convention to constrain THEIR thinking ... whereas _NTPs are more likely to do an end-run around traditional, conventional OBSTACLES to implementing Authorial Intent in various domains of Application of Logic.
For at least a half century _NTPs have been able to do an end-run around the conventional/traditional head-binding dumb-idea obstacles (mis)taught, maintained, (mis)used and ENSHRINED by _NTJ dumb asses supposed/alleged to honor and value first principles over AUTHORITY as much as _NTPs: Lisp notation and APL notation to name just two.
Insomuch as PEMDAS encoding `is' or qualifies-as `logical' it `is' illogical in that is discounts authorial intent in favor of head-binding to asinine, mediocre conventions which J types can rote memorize sans understanding and exploiting firstER principles such as communitivity and associativity while allowing notation-induced superstition to THRIVE (EG the PEMDAS expression presented ALSO mis-ues infix notation which tends to induce the superstition that ALL the operations either ARE or MUST be performed in a pairwise and/or sequential manner as if commutivity and associativity were not operative and available for exploitation).

That division is even allowed to STAND unchallenged is a travesty of logic and the ad hoc artistic composition of symbolic expressions:

a / b * c == a * 1/b * c, where 1/b is the reciprocal of b as computable via Cray supercomputer in a flash, supplantive of CPU cycles wasted by long division algorithms.

When a, 1/b, and c can be moved around -- commuted -- freely within an expression as per multiplication-preclusive-of-division the dumb ass, dumb idea encoded in sacred PEMDAS notation in the form of sacred pro forma `precedence' becomes MOOT!

As an INTP familiar with myriad notations for expressing semantic equivalents, the composibility of symbolic expressions has precedence -- vis-a-vis first principles -- over `authority' to which _NTJ's slavishly acquiesce when they pander to PEMDAS notation ... with Linguistic Relativity firmly in mind.

Those who honor logic over slavish acquiescence to Sacred Notation eschew PEMDAS and take their mathematical notions off for implementation via Better Options which allow the practical application of computers via programming languages, math apps and such.

Most of us are accessing the `content' of this thread via web browsers capable of javaScript, but how many have re-expressed the semantic of "6÷2(1+2)" via a javascript url?

How LOGICAL seem we -- all of us -- to so fixate on the PEMDAS expression of the semantic that it never even crosses our minds to re-express it in a copy-then-paste form which those challenged by this silliness can paste into the address bar of the same web browser used to read this thread?!

I'll start us off for those who'd like a proof of concept as inspiration to edit and mutate the expression provided:
Code:
javascript:2+2
Dumb idea! ... mumble grumble.
Using a web browser to access `content' and distribute malware BUT NOT re-express the semantics of a symbolic expression MAL-expressed via PEMDAS in a machine readable, machine-executable form.

How effin `logical' is this for NT/(ir)rationals?
 
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Math/CS student here.

0/0 is indeterminate. It does not equal 1, 0, nor is it undefined.

Why?
1. lim(x -> 0) 0/x = 0.
2. lim(x -> 0) x/x = 1.
3. lim(x -> 0) x/0 = undefined
4. lim(x -> 0) (x^2)/x = 0
5. lim(x -> 0) sinx/x = 1.
6. lim(x -> 10) (10-x)/(100 - x^2) = 1/20

As you can see, it's all over the place. There are an infinite number of values 0/0 could take, therefore it is indeterminate.
 

gps

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I'll start us off for those who'd like a proof of concept as inspiration to edit and mutate the expression provided:
Code:
javascript:2+2

No takers?
Code:
javascript:6/2*(1+2)
Code:
javascript:(6/2)*(1+2)
Here's the variant where division is replaced with a reciprocal which can be commuted along with other multiplied factors:
Code:
javascript:6*(1/2)*(1+2)

Now we can commute any/all of our 3 terms as per whim:
Code:
javascript:(1/2)*(1+2)*6
Code:
javascript:(1+2)*6*(1/2)
 
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